The assignment nums = nums[::-1] would be equivalent to create a new list in memory (with the elements reversed), and changing the pointer nums to point to that new list.
A series of expressions connected by or s evaluates to the leftmost expression that has a "truthy" value - which for numeric types, means "nonzero". So this is equal to nums[I - 1] if that isn't zero, otherwise 1.
Question : Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length. Do not allocate extra space for another array, you must do ...
I was working on TwoSum problem of LeetCode Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
How do I access the index while iterating over a sequence with a for loop? xs = [8, 23, 45] for x in xs: print("item #{} = {}".format(index, x)) Desired output: item #1 = 8 item #2 ...
I have been trying out this problem on leetcode. 238.Product of array except self Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the element...
I'm currently trying to solve the "three sum" challenge (I'm using java by the way). Here is the challenge description: Given an array nums of n integers, are there elements a, b, c in nums such ...
I'm trying to do a LeetCode Two Sum question: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two n...
So, the code calculates the sum of the current list element nums[i] and the previous list element nums[i-1]. Then, the current list element nums[i] is replaced with that new value.
Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct. Leetcode Asked 2 years, 8 months ago Modified 2 years, 8 months ago Viewed 6k times
